# Python Coding Challenge: Two People with the Same Birthday

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Python Coding Challenge: You’re in New York City. You walk up to a stranger and ask them what their birthday is. If their birthday is the same as yours, you win. If not, you take their hand and the two of you walk up to another stranger and ask them their birthday. If their birthday is the same as either of yours, you win. If not, one of you takes their hand, and you walk up to another stranger… Keep going until you find someone who has the same birthday as someone else in your group. Use Python to figure out how many tries it will take you.

Give it a try and then check out the possible solution below the image:

### One Possible Solution

``````import random

attempts = []
for i in range(10000):
bd = random.randint(1, 366)
bds = [bd]
while True:
bd = random.randint(1, 366)
if bd not in bds:
bds.append(bd)
else:
break
attempts.append(len(bds))

sum(attempts) / len(attempts), max(attempts)``````

For me, this output: `23.7019, 77`

So, on average, it should take 23 to 24 tries to find someone. Now, go give it a try for real and see if that’s right.